Matematika Sekolah Dasar Q.Siang[tex] \sqrt{36} \times \sqrt[3]{24.389} - \sqrt{4} = [/tex][tex] {23}^{2} \times {5}^{3} + {3}^{4} = [/tex]~Dahlah Abisin Poin aja dah gak bisa jadi Mod~Nt:Pakai Cara,No COPAS,No ngasal,Good Luck​

pasqualejaskolskiulv – June 05, 2023

Q.Siang


[tex] \sqrt{36} \times \sqrt[3]{24.389} - \sqrt{4} = [/tex]
[tex] {23}^{2} \times {5}^{3} + {3}^{4} = [/tex]


~Dahlah Abisin Poin aja dah gak bisa jadi Mod~

Nt:Pakai Cara,No COPAS,No ngasal,Good Luck​

Jawaban:

1.) √36 × ³√23.389 - √4

√6² × √29³ - √2²

6 × 29 - 2

174 - 2

=> 172

2.) 23² × 5³ + 3⁴

(23.23) × (5.5.5) + (3.3.3.3)

529 × 125 + 81

66.125 + 81

=> 66.206

Penjelasan dengan langkah-langkah:

» Punya Mona Canz «

[tex] \sqrt{36} \times \sqrt[3]{24.389} - \sqrt{4} \\ =6 \times 29 - 2 \\ = 174 - 2 \\ = 172[/tex]

[tex]{23}^{2} \times {5}^{3} + {3}^{4} \\ = (23 \times 23) \times (5 \times 5 \times 5) + (3 \times 3 \times 3 \times 3) \\ = 529 \times (25 \times 5) + (9 \times 9) \\ = 529 \times 125 + 81 \\ = 66.125 + 81 \\ = 66.206[/tex]

#Koreksi

[answer.2.content]